0=15x^2-44x-20

Solution for 0=15x^2-44x-20 equation:

0=15x^2-44x-20

We move all terms to the left:

0-(15x^2-44x-20)=0

We add all the numbers together, and all the variables

-(15x^2-44x-20)=0

We get rid of parentheses

-15x^2+44x+20=0

a = -15; b = 44; c = +20;
Δ = b2-4ac
Δ = 442-4·(-15)·20
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-56}{2*-15}=\frac{-100}{-30}
=3+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+56}{2*-15}=\frac{12}{-30}
=-2/5
$